Solution :
Since given hyperbola xy = 8 is rectangular hyperbola.
And eccentricity of rectangular hyperbola is √2
Angle between asymptotes of hyperbola is 2sec−1(e)
⟹ θ = 2sec−1(√2)
⟹ θ = 2sec−1(sec45)
⟹ θ = 2(45) = 90
Similar Questions
Find the normal to the hyperbola x216 – y29 = 1 whose slope is 1.
The eccentricity of the conjugate hyperbola to the hyperbola x2−3y2 = 1 is