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What is the General Solution of Cotθ = 0 ?

Solution :

The general solution of cotθ = 0 is given by θ = (2n+1)π2, n Z.

Proof :

We have,theta

cotθ = OMPM

   cotθ = 0

  OMPM = 0

OM = 0

  OP coincides with OY or OY’

  θ = ±π2, ±3π2, ±5π2, …….

θ = (2n+1)π2,  n Z

Hence, θ = (2n+1)π2,  n Z is the general solution of cotθ = 0.

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