The value of $tan^{-1}(1)$ + $cos^{-1}({-1\over 2})$ + $sin^{-1}({-1\over 2})$ is equal to

Solution :

We have, $tan^{-1}(1)$ + $cos^{-1}({-1\over 2})$ + $sin^{-1}({-1\over 2})$

= $\pi\over 4$ + $2\pi\over 3$ – $\pi\over 6$ = $3\pi\over 4$

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