What is the integration of x tan inverse x dx ?
Solution : Let I = \(\int\) x\(tan^{-1}x\) dx By using Integration by parts rule, Taking tan inverse x as first function and x as second function. Then, I = (\(tan^{-1}x\)) \(\int\) x dx – \(\int\){\({d\over dx}\)(\(tan^{-1}x\) \(\int\) x dx} dx I = (\(tan^{-1}x\))\(x^2\over 2\) – \(\int\)\({1\over 1 + x^2}\) \(\times\) \(x^2\over 2\) dx \(\implies\) I […]
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