Here, you will learn learn formula for variance and standard deviation and relationship between variance and standard deviation.
Let’s begin –
Variance and Standard Deviation :
The variance of a distribution is, the mean of squares of deviation of variate from their mean. It is denoted by \(\sigma^2\) or var(x).
The positive square root of the variance are called the standard deviation. It is denoted by \(\sigma\) or S.D.
Hence standard deviation = + \(\sqrt{variance}\)
Formula for Variance :
(i) for ungrouped distribution :
\({\sigma^2}_x\) = \(\sum(x_i – \bar{x})^2\over n\)
\({\sigma^2}_x\) = \(\sum{x_i}^2\over n\) – \(\bar{x}^2\)
= \(\sum{x_i}^2\over n\) – \(({\sum{x_i}\over n})^2\)
\({\sigma^2}_d\) = \(\sum{d_i}^2\over n\) – \(({\sum{d_i}\over n})^2\), where \(d_i\) = \(x_i\) – a
(ii) for frequency distribution :
\({\sigma^2}_x\) = \(\sum f_i(x_i – \bar{x})^2\over N\)
\({\sigma^2}_x\) = \(\sum f_i{x_i}^2\over N\) – \(\bar{x}^2\)
= \(\sum f_i{x_i}^2\over N\) – \(({\sum f_i{x_i}\over N})^2\)
\({\sigma^2}_d\) = \(\sum f_i{d_i}^2\over n\) – \(({\sum f_i{d_i}\over n})^2\), where \(d_i\) = \(x_i\) – a
\({\sigma^2}_d\) = \(h^2\)[\(\sum f_i{u_i}^2\over n\) – \(({\sum f_i{u_i}\over n})^2\)], where \(u_i\) = \(x_i\over h\)
(iii) Coefficient of Standard Deviation = \(\sigma\over \bar{x}\)
Coefficient of variation = \(\sigma\over \bar{x}\) \(\times\) 100 (in percentage)
Example : Find the variance and standard deviation of first n natural numbers.
Solution : We know that,
\({\sigma^2}_x\) = \(\sum{x_i}^2\over n\) – \(({\sum{x_i}\over n})^2\)
= \(\sum{n}^2\over n\) – \(({\sum{n}\over n})^2\) = \(n(n + 1)(2n + 1)\over {6n}\) – \([{n(n + 1)\over {2n}}]^2\) = \(n^2 – 1\over 12\)
Standard Deviation = \(\sqrt{variance}\) = \(\sqrt{n^2 – 1\over 12}\)
Example : Find the Coefficient of variation in percentage of first n natural numbers.
Solution : We know that
Mean \(\bar{x}\) = \(n + 1\over 2\),
Variance = \({\sigma^2}_x\) = \(n^2 – 1\over 12\)
Standard Deviation \(\sigma\) = \(\sqrt{variance}\) = \(\sqrt{n^2 – 1\over 12}\)
Coefficient of variation = \(\sigma\over \bar{x}\) \(\times\) 100
= \(\sqrt{n^2 – 1\over 12}\) \(\times\) (\(2\over n + 1\)) \(\times\) 100
= \(\sqrt{(n – 1)\over 3(n + 1)}\) \(\times\) 100
Hope you learnt what is the formula for variance and standard deviation, learn more concepts of statistics and practice more questions to get ahead in the competition. Good luck!