Solution :
The equation of the given curve is
y = 2x2+3sinx ……….(i)
Putting x = 0 in (i), we get y = 0.
So, the point of contact is (0, 0).
Now, y = 2x2+3sinx
Differentiating with respect to x,
⟹ dydx = 4x + 3 cos x
⟹ (dydx)(0,0) = 4 × 0 + 3 cos 0 = 3
So, the equation of the normal at (0, 0) is
y – 0 = -13(x – 0) or, x + 3y = 0
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