Evaluate the given log : \(81^{l\over {log_5 3}}\) + \(27^{log_9 36}\) + \(3^{4\over {log_7 9}}\).

Solution :

\(81^{log_3 5}\) + \(3^{3log_9 36}\) + \(3^{4log_9 7}\)

\(\implies\) \(3^{4log_3 5}\) + \(3^{log_3 {(36)}^{3/2}}\) + \(3^{log_3 {7}^2}\)

= 625 + 216 + 49 = 890.

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