Here you will learn differentiation of exponential function by using first principle and its examples.
Let’s begin –
Differentiation of Exponential Function
(1) Differentiation of ex :
The differentiation of ex with respect to x is ex.
i.e. ddx ex = ex
Proof Using first Principle :
Let f(x) = ex. Then, f(x + h) = ex+h
∴ ddx(f(x)) = limh→0 f(x+h)–f(x)h
ddx(f(x)) = limh→0 ex+h–exh
ddx(f(x)) = limh→0 ex.eh–exh
ddx(f(x)) = limh→0 ex (eh–1h)
⟹ ddx(f(x)) = ex limh→0 (eh–1h)
because, [limh→0(eh–1h) = 1]
⟹ ddx(f(x)) = ex × 1 = ex
Hence, ddx (ex) = ex
Example : What is the differentiation of e2x ?
Solution : Let y = e2x
ddx (y) = ddx e2x
By using chain rule,
ddx (y) = 2e2x
Hence, ddx (e2x) = 2e2x
(2) Differentiation of ax :
The differentiation of ax with respect to x is axlogea.
i.e. ddx ax = axlogea
Proof Using first Principle :
Let f(x) = ax. Then, f(x + h) = ax+h
∴ ddx(f(x)) = limh→0 f(x+h)–f(x)h
ddx(f(x)) = limh→0 ax+h–axh
ddx(f(x)) = limh→0 ax.ah–axh
ddx(f(x)) = limh→0 ax (ah–1h)
⟹ ddx(f(x)) = ax limh→0 (ah–1h)
because, [limh→0(ah–1h) = logea]
⟹ ddx(f(x)) = ax × logea = ax logea
Hence, ddx (ax) = ax logea
Example : What is the differentiation of 5x ?
Solution : Let y = 5x
ddx (y) = ddx 5x
ddx (y) = 5xloge5
Hence, ddx (5x) = 5xloge5