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Differentiation of Exponential Function

Here you will learn differentiation of exponential function by using first principle and its examples.

Let’s begin –

Differentiation of Exponential Function

(1) Differentiation of ex :

The differentiation of ex with respect to x is ex.

i.e. ddx ex = ex

Proof Using first Principle :

Let f(x) = ex. Then, f(x + h) = ex+h

   ddx(f(x)) = limh0 f(x+h)f(x)h

ddx(f(x)) = limh0 ex+hexh

ddx(f(x)) = limh0 ex.ehexh

ddx(f(x)) = limh0 ex (eh1h)

ddx(f(x)) = ex  limh0 (eh1h)

because, [limh0(eh1h) = 1]

ddx(f(x)) = ex × 1 = ex

Hence, ddx (ex) = ex

Example : What is the differentiation of e2x ?

Solution : Let y  = e2x

ddx (y) = ddx e2x

By using chain rule,

ddx (y) = 2e2x

Hence, ddx (e2x) = 2e2x

(2) Differentiation of ax :

The differentiation of ax with respect to x is axlogea.

i.e. ddx ax = axlogea

Proof Using first Principle :

Let f(x) = ax. Then, f(x + h) = ax+h

   ddx(f(x)) = limh0 f(x+h)f(x)h

ddx(f(x)) = limh0 ax+haxh

ddx(f(x)) = limh0 ax.ahaxh

ddx(f(x)) = limh0 ax (ah1h)

ddx(f(x)) = ax  limh0 (ah1h)

because, [limh0(ah1h) = logea]

ddx(f(x)) = ax × logea = ax logea

Hence, ddx (ax) = ax logea

Example : What is the differentiation of 5x ?

Solution : Let y  = 5x

ddx (y) = ddx 5x

ddx (y) = 5xloge5

Hence, ddx (5x) = 5xloge5


Related Questions

What is the differentiation of esinx ?

What is the integration of ex ?

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