Solve : 6 – 10cosx = 3\(sin^2x\)
Solution : we have, 6 – 10cosx = 3\(sin^2x\) \(\therefore\) 6 – 10cosx = 3 – 3\(cos^2x\) \(\implies\) 3\(cos^2x\) – 10cosx + 3 = 0 \(\implies\) (3cosx-1)(cosx-3) = 0 \(\implies\) cosx = \(1\over 3\) or cosx = 3 Since cosx = 3 is not possible as -1 \(\le\) cosx \(\le\) 1 \(\therefore\) cosx = \(1\over […]
Solve : 6 – 10cosx = 3\(sin^2x\) Read More »