## If mean of the series $$x_1$$, $$x^2$$, ….. , $$x_n$$ is $$\bar{x}$$, then the mean of the series $$x_i$$ + 2i, i = 1, 2, ……, n will be

Solution : As given $$\bar{x}$$ = $$x_1 + x_2 + …. + x_n\over n$$ If the mean of the series $$x_i$$ + 2i, i = 1, 2, ….., n be $$\bar{X}$$, then $$\bar{X}$$ = $$(x_1+2) + (x_2+2.2) + (x_3+2.3) + …. + (x_n + 2.n)\over n$$ = $$x_1 + x_2 + …. + x_n\over n$$ …