## Tick the correct answer and justify : In \(\triangle\), AB = \(6\sqrt{3}\) cm, AC = 12 cm and BC = 6 cm. The angle is : (i) 120 (ii) 60 (iii) 90 (iv) 45

Solution : In triangle ABC, we have : AB = \(6\sqrt{3}\) cm , AC = 12 cm and BC = 6 cm Now, \({AB}^2\) + \({BC}^2\) = \((6\sqrt{3})^2\) + \((6)^2\) = \(36 \times 3\) + 36 = 108 + 36 = 144 = \((AC)^2\) Thus, triangle ABC is a right angled triangle at B. \(\therefore\) …