Maths Questions

What is the equation of common tangent to the parabola \(y^2\) = 4ax and \(x^2\) = 4ay ?

Solution : The equation of tangent in slope form to \(y^2\) = 4ax is y = mx + \(a\over m\) Now, if it is common to both parabola, it also lies on second parabola then \(x^2\) = 4a(mx + \(a\over m\)) \(mx^2 – 4am^2 – 4a^2\) = 0 has equal roots. then its discriminant is …

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What is the equation of tangent to the parabola having slope m?

Solution : The Equation of tangent to the parabola having slope ‘m’, is y = mx + \(a\over m\) ,  (m \(\ne\) 0) and point of contact  is (\(a\over m^2\), \(2a\over m\)). Similar Questions The sum of the slopes of the tangent of the parabola \(y^2\)=4ax drawn from the point (2,3) is Find the locus …

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If the lines 3x-4y-7=0 and 2x-3y-5=0 are two diameters of a circle of area 49π square units, then what is the equation of the circle?

Solution : Area = 49π π\(r^2\) = 49π r = 7 Now find the coordinates of center of circle by solving the given two equations of diameter. By solving the above equation through elimination method we get, x = 1 and y =-1 which are the coordinates of center of circle. Now the general equation …

If the lines 3x-4y-7=0 and 2x-3y-5=0 are two diameters of a circle of area 49π square units, then what is the equation of the circle? Read More »